Change endpoint from persons to people

backend/apis/nodejs/node_modules/diff-sequences/LICENSE

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+MIT License
+
+Copyright (c) Meta Platforms, Inc. and affiliates.
+
+Permission is hereby granted, free of charge, to any person obtaining a copy
+of this software and associated documentation files (the "Software"), to deal
+in the Software without restriction, including without limitation the rights
+to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
+copies of the Software, and to permit persons to whom the Software is
+furnished to do so, subject to the following conditions:
+
+The above copyright notice and this permission notice shall be included in all
+copies or substantial portions of the Software.
+
+THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
+IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
+FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
+AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
+LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
+OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
+SOFTWARE.

backend/apis/nodejs/node_modules/diff-sequences/README.md

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+# diff-sequences
+
+Compare items in two sequences to find a **longest common subsequence**.
+
+The items not in common are the items to delete or insert in a **shortest edit script**.
+
+To maximize flexibility and minimize memory, you write **callback** functions as configuration:
+
+**Input** function `isCommon(aIndex, bIndex)` compares items at indexes in the sequences and returns a truthy/falsey value. This package might call your function more than once for some pairs of indexes.
+
+- Because your function encapsulates **comparison**, this package can compare items according to `===` operator, `Object.is` method, or other criterion.
+- Because your function encapsulates **sequences**, this package can find differences in arrays, strings, or other data.
+
+**Output** function `foundSubsequence(nCommon, aCommon, bCommon)` receives the number of adjacent items and starting indexes of each common subsequence. If sequences do not have common items, then this package does not call your function.
+
+If N is the sum of lengths of sequences and L is length of a longest common subsequence, then D = N – 2L is the number of **differences** in the corresponding shortest edit script.
+
+[_An O(ND) Difference Algorithm and Its Variations_](http://xmailserver.org/diff2.pdf) by Eugene W. Myers is fast when sequences have **few** differences.
+
+This package implements the **linear space** variation with optimizations so it is fast even when sequences have **many** differences.
+
+## Usage
+
+To add this package as a dependency of a project, do either of the following:
+
+- `npm install diff-sequences`
+- `yarn add diff-sequences`
+
+To use `diff` as the name of the default export from this package, do either of the following:
+
+- `var diff = require('diff-sequences').default; // CommonJS modules`
+- `import diff from 'diff-sequences'; // ECMAScript modules`
+
+Call `diff` with the **lengths** of sequences and your **callback** functions:
+
+```js
+const a = ['a', 'b', 'c', 'a', 'b', 'b', 'a'];
+const b = ['c', 'b', 'a', 'b', 'a', 'c'];
+
+function isCommon(aIndex, bIndex) {
+  return a[aIndex] === b[bIndex];
+}
+function foundSubsequence(nCommon, aCommon, bCommon) {
+  // see examples
+}
+
+diff(a.length, b.length, isCommon, foundSubsequence);
+```
+
+## Example of longest common subsequence
+
+Some sequences (for example, `a` and `b` in the example of usage) have more than one longest common subsequence.
+
+This package finds the following common items:
+
+| comparisons of common items      | values     |            output arguments |
+| :------------------------------- | :--------- | --------------------------: |
+| `a[2] === b[0]`                  | `'c'`      | `foundSubsequence(1, 2, 0)` |
+| `a[4] === b[1]`                  | `'b'`      | `foundSubsequence(1, 4, 1)` |
+| `a[5] === b[3] && a[6] === b[4]` | `'b', 'a'` | `foundSubsequence(2, 5, 3)` |
+
+The “edit graph” analogy in the Myers paper shows the following common items:
+
+| comparisons of common items      | values     |
+| :------------------------------- | :--------- |
+| `a[2] === b[0]`                  | `'c'`      |
+| `a[3] === b[2] && a[4] === b[3]` | `'a', 'b'` |
+| `a[6] === b[4]`                  | `'a'`      |
+
+Various packages which implement the Myers algorithm will **always agree** on the **length** of a longest common subsequence, but might **sometimes disagree** on which **items** are in it.
+
+## Example of callback functions to count common items
+
+```js
+// Return length of longest common subsequence according to === operator.
+function countCommonItems(a, b) {
+  let n = 0;
+  function isCommon(aIndex, bIndex) {
+    return a[aIndex] === b[bIndex];
+  }
+  function foundSubsequence(nCommon) {
+    n += nCommon;
+  }
+
+  diff(a.length, b.length, isCommon, foundSubsequence);
+
+  return n;
+}
+
+const commonLength = countCommonItems(
+  ['a', 'b', 'c', 'a', 'b', 'b', 'a'],
+  ['c', 'b', 'a', 'b', 'a', 'c'],
+);
+```
+
+| category of items  |                expression | value |
+| :----------------- | ------------------------: | ----: |
+| in common          |            `commonLength` |   `4` |
+| to delete from `a` | `a.length - commonLength` |   `3` |
+| to insert from `b` | `b.length - commonLength` |   `2` |
+
+If the length difference `b.length - a.length` is:
+
+- negative: its absolute value is the minimum number of items to **delete** from `a`
+- positive: it is the minimum number of items to **insert** from `b`
+- zero: there is an **equal** number of items to delete from `a` and insert from `b`
+- non-zero: there is an equal number of **additional** items to delete from `a` and insert from `b`
+
+In this example, `6 - 7` is:
+
+- negative: `1` is the minimum number of items to **delete** from `a`
+- non-zero: `2` is the number of **additional** items to delete from `a` and insert from `b`
+
+## Example of callback functions to find common items
+
+```js
+// Return array of items in longest common subsequence according to Object.is method.
+const findCommonItems = (a, b) => {
+  const array = [];
+  diff(
+    a.length,
+    b.length,
+    (aIndex, bIndex) => Object.is(a[aIndex], b[bIndex]),
+    (nCommon, aCommon) => {
+      for (; nCommon !== 0; nCommon -= 1, aCommon += 1) {
+        array.push(a[aCommon]);
+      }
+    },
+  );
+  return array;
+};
+
+const commonItems = findCommonItems(
+  ['a', 'b', 'c', 'a', 'b', 'b', 'a'],
+  ['c', 'b', 'a', 'b', 'a', 'c'],
+);
+```
+
+| `i` | `commonItems[i]` | `aIndex` |
+| --: | :--------------- | -------: |
+| `0` | `'c'`            |      `2` |
+| `1` | `'b'`            |      `4` |
+| `2` | `'b'`            |      `5` |
+| `3` | `'a'`            |      `6` |
+
+## Example of callback functions to diff index intervals
+
+Instead of slicing array-like objects, you can adjust indexes in your callback functions.
+
+```js
+// Diff index intervals that are half open [start, end) like array slice method.
+const diffIndexIntervals = (a, aStart, aEnd, b, bStart, bEnd) => {
+  // Validate: 0 <= aStart and aStart <= aEnd and aEnd <= a.length
+  // Validate: 0 <= bStart and bStart <= bEnd and bEnd <= b.length
+
+  diff(
+    aEnd - aStart,
+    bEnd - bStart,
+    (aIndex, bIndex) => Object.is(a[aStart + aIndex], b[bStart + bIndex]),
+    (nCommon, aCommon, bCommon) => {
+      // aStart + aCommon, bStart + bCommon
+    },
+  );
+
+  // After the last common subsequence, do any remaining work.
+};
+```
+
+## Example of callback functions to emulate diff command
+
+Linux or Unix has a `diff` command to compare files line by line. Its output is a **shortest edit script**:
+
+- **c**hange adjacent lines from the first file to lines from the second file
+- **d**elete lines from the first file
+- **a**ppend or insert lines from the second file
+
+```js
+// Given zero-based half-open range [start, end) of array indexes,
+// return one-based closed range [start + 1, end] as string.
+const getRange = (start, end) =>
+  start + 1 === end ? `${start + 1}` : `${start + 1},${end}`;
+
+// Given index intervals of lines to delete or insert, or both, or neither,
+// push formatted diff lines onto array.
+const pushDelIns = (aLines, aIndex, aEnd, bLines, bIndex, bEnd, array) => {
+  const deleteLines = aIndex !== aEnd;
+  const insertLines = bIndex !== bEnd;
+  const changeLines = deleteLines && insertLines;
+  if (changeLines) {
+    array.push(`${getRange(aIndex, aEnd)}c${getRange(bIndex, bEnd)}`);
+  } else if (deleteLines) {
+    array.push(`${getRange(aIndex, aEnd)}d${String(bIndex)}`);
+  } else if (insertLines) {
+    array.push(`${String(aIndex)}a${getRange(bIndex, bEnd)}`);
+  } else {
+    return;
+  }
+
+  for (; aIndex !== aEnd; aIndex += 1) {
+    array.push(`< ${aLines[aIndex]}`); // delete is less than
+  }
+
+  if (changeLines) {
+    array.push('---');
+  }
+
+  for (; bIndex !== bEnd; bIndex += 1) {
+    array.push(`> ${bLines[bIndex]}`); // insert is greater than
+  }
+};
+
+// Given content of two files, return emulated output of diff utility.
+const findShortestEditScript = (a, b) => {
+  const aLines = a.split('\n');
+  const bLines = b.split('\n');
+  const aLength = aLines.length;
+  const bLength = bLines.length;
+
+  const isCommon = (aIndex, bIndex) => aLines[aIndex] === bLines[bIndex];
+
+  let aIndex = 0;
+  let bIndex = 0;
+  const array = [];
+  const foundSubsequence = (nCommon, aCommon, bCommon) => {
+    pushDelIns(aLines, aIndex, aCommon, bLines, bIndex, bCommon, array);
+    aIndex = aCommon + nCommon; // number of lines compared in a
+    bIndex = bCommon + nCommon; // number of lines compared in b
+  };
+
+  diff(aLength, bLength, isCommon, foundSubsequence);
+
+  // After the last common subsequence, push remaining change lines.
+  pushDelIns(aLines, aIndex, aLength, bLines, bIndex, bLength, array);
+
+  return array.length === 0 ? '' : `${array.join('\n')}\n`;
+};
+```
+
+## Example of callback functions to format diff lines
+
+Here is simplified code to format **changed and unchanged lines** in expected and received values after a test fails in Jest:
+
+```js
+// Format diff with minus or plus for change lines and space for common lines.
+const formatDiffLines = (a, b) => {
+  // Jest depends on pretty-format package to serialize objects as strings.
+  // Unindented for comparison to avoid distracting differences:
+  const aLinesUn = format(a, {indent: 0 /*, other options*/}).split('\n');
+  const bLinesUn = format(b, {indent: 0 /*, other options*/}).split('\n');
+  // Indented to display changed and unchanged lines:
+  const aLinesIn = format(a, {indent: 2 /*, other options*/}).split('\n');
+  const bLinesIn = format(b, {indent: 2 /*, other options*/}).split('\n');
+
+  const aLength = aLinesIn.length; // Validate: aLinesUn.length === aLength
+  const bLength = bLinesIn.length; // Validate: bLinesUn.length === bLength
+
+  const isCommon = (aIndex, bIndex) => aLinesUn[aIndex] === bLinesUn[bIndex];
+
+  // Only because the GitHub Flavored Markdown doc collapses adjacent spaces,
+  // this example code and the following table represent spaces as middle dots.
+  let aIndex = 0;
+  let bIndex = 0;
+  const array = [];
+  const foundSubsequence = (nCommon, aCommon, bCommon) => {
+    for (; aIndex !== aCommon; aIndex += 1) {
+      array.push(`-·${aLinesIn[aIndex]}`); // delete is minus
+    }
+    for (; bIndex !== bCommon; bIndex += 1) {
+      array.push(`+·${bLinesIn[bIndex]}`); // insert is plus
+    }
+    for (; nCommon !== 0; nCommon -= 1, aIndex += 1, bIndex += 1) {
+      // For common lines, received indentation seems more intuitive.
+      array.push(`··${bLinesIn[bIndex]}`); // common is space
+    }
+  };
+
+  diff(aLength, bLength, isCommon, foundSubsequence);
+
+  // After the last common subsequence, push remaining change lines.
+  for (; aIndex !== aLength; aIndex += 1) {
+    array.push(`-·${aLinesIn[aIndex]}`);
+  }
+  for (; bIndex !== bLength; bIndex += 1) {
+    array.push(`+·${bLinesIn[bIndex]}`);
+  }
+
+  return array;
+};
+
+const expected = {
+  searching: '',
+  sorting: {
+    ascending: true,
+    fieldKey: 'what',
+  },
+};
+const received = {
+  searching: '',
+  sorting: [
+    {
+      descending: false,
+      fieldKey: 'what',
+    },
+  ],
+};
+
+const diffLines = formatDiffLines(expected, received);
+```
+
+If N is the sum of lengths of sequences and L is length of a longest common subsequence, then N – L is length of an array of diff lines. In this example, N is 7 + 9, L is 5, and N – L is 11.
+
+|  `i` | `diffLines[i]`                     | `aIndex` | `bIndex` |
+| ---: | :--------------------------------- | -------: | -------: |
+|  `0` | `'··Object {'`                     |      `0` |      `0` |
+|  `1` | `'····"searching": "",'`           |      `1` |      `1` |
+|  `2` | `'-···"sorting": Object {'`        |      `2` |          |
+|  `3` | `'-·····"ascending": true,'`       |      `3` |          |
+|  `4` | `'+·····"sorting": Array ['`       |          |      `2` |
+|  `5` | `'+·······Object {'`               |          |      `3` |
+|  `6` | `'+·········"descending": false,'` |          |      `4` |
+|  `7` | `'··········"fieldKey": "what",'`  |      `4` |      `5` |
+|  `8` | `'········},'`                     |      `5` |      `6` |
+|  `9` | `'+·····],'`                       |          |      `7` |
+| `10` | `'··}'`                            |      `6` |      `8` |
+
+## Example of callback functions to find diff items
+
+Here is simplified code to find changed and unchanged substrings **within adjacent changed lines** in expected and received values after a test fails in Jest:
+
+```js
+// Return diff items for strings (compatible with diff-match-patch package).
+const findDiffItems = (a, b) => {
+  const isCommon = (aIndex, bIndex) => a[aIndex] === b[bIndex];
+
+  let aIndex = 0;
+  let bIndex = 0;
+  const array = [];
+  const foundSubsequence = (nCommon, aCommon, bCommon) => {
+    if (aIndex !== aCommon) {
+      array.push([-1, a.slice(aIndex, aCommon)]); // delete is -1
+    }
+    if (bIndex !== bCommon) {
+      array.push([1, b.slice(bIndex, bCommon)]); // insert is 1
+    }
+
+    aIndex = aCommon + nCommon; // number of characters compared in a
+    bIndex = bCommon + nCommon; // number of characters compared in b
+    array.push([0, a.slice(aCommon, aIndex)]); // common is 0
+  };
+
+  diff(a.length, b.length, isCommon, foundSubsequence);
+
+  // After the last common subsequence, push remaining change items.
+  if (aIndex !== a.length) {
+    array.push([-1, a.slice(aIndex)]);
+  }
+  if (bIndex !== b.length) {
+    array.push([1, b.slice(bIndex)]);
+  }
+
+  return array;
+};
+
+const expectedDeleted = ['"sorting": Object {', '"ascending": true,'].join(
+  '\n',
+);
+const receivedInserted = [
+  '"sorting": Array [',
+  'Object {',
+  '"descending": false,',
+].join('\n');
+
+const diffItems = findDiffItems(expectedDeleted, receivedInserted);
+```
+
+| `i` | `diffItems[i][0]` | `diffItems[i][1]` |
+| --: | ----------------: | :---------------- |
+| `0` |               `0` | `'"sorting": '`   |
+| `1` |               `1` | `'Array [\n'`     |
+| `2` |               `0` | `'Object {\n"'`   |
+| `3` |              `-1` | `'a'`             |
+| `4` |               `1` | `'de'`            |
+| `5` |               `0` | `'scending": '`   |
+| `6` |              `-1` | `'tru'`           |
+| `7` |               `1` | `'fals'`          |
+| `8` |               `0` | `'e,'`            |
+
+The length difference `b.length - a.length` is equal to the sum of `diffItems[i][0]` values times `diffItems[i][1]` lengths. In this example, the difference `48 - 38` is equal to the sum `10`.
+
+| category of diff item | `[0]` |      `[1]` lengths | subtotal |
+| :-------------------- | ----: | -----------------: | -------: |
+| in common             |   `0` | `11 + 10 + 11 + 2` |      `0` |
+| to delete from `a`    |  `–1` |            `1 + 3` |     `-4` |
+| to insert from `b`    |   `1` |        `8 + 2 + 4` |     `14` |
+
+Instead of formatting the changed substrings with escape codes for colors in the `foundSubsequence` function to save memory, this example spends memory to **gain flexibility** before formatting, so a separate heuristic algorithm might modify the generic array of diff items to show changes more clearly:
+
+| `i` | `diffItems[i][0]` | `diffItems[i][1]` |
+| --: | ----------------: | :---------------- |
+| `6` |              `-1` | `'true'`          |
+| `7` |               `1` | `'false'`         |
+| `8` |               `0` | `','`             |
+
+For expected and received strings of serialized data, the result of finding changed **lines**, and then finding changed **substrings** within adjacent changed lines (as in the preceding two examples) sometimes displays the changes in a more intuitive way than the result of finding changed substrings, and then splitting them into changed and unchanged lines.

backend/apis/nodejs/node_modules/diff-sequences/build/index.d.ts

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+/**
+ * Copyright (c) Meta Platforms, Inc. and affiliates.
+ *
+ * This source code is licensed under the MIT license found in the
+ * LICENSE file in the root directory of this source tree.
+ */
+export declare type Callbacks = {
+  foundSubsequence: FoundSubsequence;
+  isCommon: IsCommon;
+};
+
+declare function diffSequence(
+  aLength: number,
+  bLength: number,
+  isCommon: IsCommon,
+  foundSubsequence: FoundSubsequence,
+): void;
+export default diffSequence;
+
+declare type FoundSubsequence = (
+  nCommon: number, // caller can assume: 0 < nCommon
+  aCommon: number, // caller can assume: 0 <= aCommon && aCommon < aLength
+  bCommon: number,
+) => void;
+
+/**
+ * Copyright (c) Meta Platforms, Inc. and affiliates.
+ *
+ * This source code is licensed under the MIT license found in the
+ * LICENSE file in the root directory of this source tree.
+ *
+ */
+declare type IsCommon = (
+  aIndex: number, // caller can assume: 0 <= aIndex && aIndex < aLength
+  bIndex: number,
+) => boolean;
+
+export {};

backend/apis/nodejs/node_modules/diff-sequences/build/index.js

@@ -0,0 +1,798 @@
+'use strict';
+
+Object.defineProperty(exports, '__esModule', {
+  value: true
+});
+exports.default = diffSequence;
+/**
+ * Copyright (c) Meta Platforms, Inc. and affiliates.
+ *
+ * This source code is licensed under the MIT license found in the
+ * LICENSE file in the root directory of this source tree.
+ *
+ */
+
+// This diff-sequences package implements the linear space variation in
+// An O(ND) Difference Algorithm and Its Variations by Eugene W. Myers
+
+// Relationship in notation between Myers paper and this package:
+// A is a
+// N is aLength, aEnd - aStart, and so on
+// x is aIndex, aFirst, aLast, and so on
+// B is b
+// M is bLength, bEnd - bStart, and so on
+// y is bIndex, bFirst, bLast, and so on
+// Δ = N - M is negative of baDeltaLength = bLength - aLength
+// D is d
+// k is kF
+// k + Δ is kF = kR - baDeltaLength
+// V is aIndexesF or aIndexesR (see comment below about Indexes type)
+// index intervals [1, N] and [1, M] are [0, aLength) and [0, bLength)
+// starting point in forward direction (0, 0) is (-1, -1)
+// starting point in reverse direction (N + 1, M + 1) is (aLength, bLength)
+
+// The “edit graph” for sequences a and b corresponds to items:
+// in a on the horizontal axis
+// in b on the vertical axis
+//
+// Given a-coordinate of a point in a diagonal, you can compute b-coordinate.
+//
+// Forward diagonals kF:
+// zero diagonal intersects top left corner
+// positive diagonals intersect top edge
+// negative diagonals insersect left edge
+//
+// Reverse diagonals kR:
+// zero diagonal intersects bottom right corner
+// positive diagonals intersect right edge
+// negative diagonals intersect bottom edge
+
+// The graph contains a directed acyclic graph of edges:
+// horizontal: delete an item from a
+// vertical: insert an item from b
+// diagonal: common item in a and b
+//
+// The algorithm solves dual problems in the graph analogy:
+// Find longest common subsequence: path with maximum number of diagonal edges
+// Find shortest edit script: path with minimum number of non-diagonal edges
+
+// Input callback function compares items at indexes in the sequences.
+
+// Output callback function receives the number of adjacent items
+// and starting indexes of each common subsequence.
+// Either original functions or wrapped to swap indexes if graph is transposed.
+// Indexes in sequence a of last point of forward or reverse paths in graph.
+// Myers algorithm indexes by diagonal k which for negative is bad deopt in V8.
+// This package indexes by iF and iR which are greater than or equal to zero.
+// and also updates the index arrays in place to cut memory in half.
+// kF = 2 * iF - d
+// kR = d - 2 * iR
+// Division of index intervals in sequences a and b at the middle change.
+// Invariant: intervals do not have common items at the start or end.
+const pkg = 'diff-sequences'; // for error messages
+const NOT_YET_SET = 0; // small int instead of undefined to avoid deopt in V8
+
+// Return the number of common items that follow in forward direction.
+// The length of what Myers paper calls a “snake” in a forward path.
+const countCommonItemsF = (aIndex, aEnd, bIndex, bEnd, isCommon) => {
+  let nCommon = 0;
+  while (aIndex < aEnd && bIndex < bEnd && isCommon(aIndex, bIndex)) {
+    aIndex += 1;
+    bIndex += 1;
+    nCommon += 1;
+  }
+  return nCommon;
+};
+
+// Return the number of common items that precede in reverse direction.
+// The length of what Myers paper calls a “snake” in a reverse path.
+const countCommonItemsR = (aStart, aIndex, bStart, bIndex, isCommon) => {
+  let nCommon = 0;
+  while (aStart <= aIndex && bStart <= bIndex && isCommon(aIndex, bIndex)) {
+    aIndex -= 1;
+    bIndex -= 1;
+    nCommon += 1;
+  }
+  return nCommon;
+};
+
+// A simple function to extend forward paths from (d - 1) to d changes
+// when forward and reverse paths cannot yet overlap.
+const extendPathsF = (
+  d,
+  aEnd,
+  bEnd,
+  bF,
+  isCommon,
+  aIndexesF,
+  iMaxF // return the value because optimization might decrease it
+) => {
+  // Unroll the first iteration.
+  let iF = 0;
+  let kF = -d; // kF = 2 * iF - d
+  let aFirst = aIndexesF[iF]; // in first iteration always insert
+  let aIndexPrev1 = aFirst; // prev value of [iF - 1] in next iteration
+  aIndexesF[iF] += countCommonItemsF(
+    aFirst + 1,
+    aEnd,
+    bF + aFirst - kF + 1,
+    bEnd,
+    isCommon
+  );
+
+  // Optimization: skip diagonals in which paths cannot ever overlap.
+  const nF = d < iMaxF ? d : iMaxF;
+
+  // The diagonals kF are odd when d is odd and even when d is even.
+  for (iF += 1, kF += 2; iF <= nF; iF += 1, kF += 2) {
+    // To get first point of path segment, move one change in forward direction
+    // from last point of previous path segment in an adjacent diagonal.
+    // In last possible iteration when iF === d and kF === d always delete.
+    if (iF !== d && aIndexPrev1 < aIndexesF[iF]) {
+      aFirst = aIndexesF[iF]; // vertical to insert from b
+    } else {
+      aFirst = aIndexPrev1 + 1; // horizontal to delete from a
+
+      if (aEnd <= aFirst) {
+        // Optimization: delete moved past right of graph.
+        return iF - 1;
+      }
+    }
+
+    // To get last point of path segment, move along diagonal of common items.
+    aIndexPrev1 = aIndexesF[iF];
+    aIndexesF[iF] =
+      aFirst +
+      countCommonItemsF(aFirst + 1, aEnd, bF + aFirst - kF + 1, bEnd, isCommon);
+  }
+  return iMaxF;
+};
+
+// A simple function to extend reverse paths from (d - 1) to d changes
+// when reverse and forward paths cannot yet overlap.
+const extendPathsR = (
+  d,
+  aStart,
+  bStart,
+  bR,
+  isCommon,
+  aIndexesR,
+  iMaxR // return the value because optimization might decrease it
+) => {
+  // Unroll the first iteration.
+  let iR = 0;
+  let kR = d; // kR = d - 2 * iR
+  let aFirst = aIndexesR[iR]; // in first iteration always insert
+  let aIndexPrev1 = aFirst; // prev value of [iR - 1] in next iteration
+  aIndexesR[iR] -= countCommonItemsR(
+    aStart,
+    aFirst - 1,
+    bStart,
+    bR + aFirst - kR - 1,
+    isCommon
+  );
+
+  // Optimization: skip diagonals in which paths cannot ever overlap.
+  const nR = d < iMaxR ? d : iMaxR;
+
+  // The diagonals kR are odd when d is odd and even when d is even.
+  for (iR += 1, kR -= 2; iR <= nR; iR += 1, kR -= 2) {
+    // To get first point of path segment, move one change in reverse direction
+    // from last point of previous path segment in an adjacent diagonal.
+    // In last possible iteration when iR === d and kR === -d always delete.
+    if (iR !== d && aIndexesR[iR] < aIndexPrev1) {
+      aFirst = aIndexesR[iR]; // vertical to insert from b
+    } else {
+      aFirst = aIndexPrev1 - 1; // horizontal to delete from a
+
+      if (aFirst < aStart) {
+        // Optimization: delete moved past left of graph.
+        return iR - 1;
+      }
+    }
+
+    // To get last point of path segment, move along diagonal of common items.
+    aIndexPrev1 = aIndexesR[iR];
+    aIndexesR[iR] =
+      aFirst -
+      countCommonItemsR(
+        aStart,
+        aFirst - 1,
+        bStart,
+        bR + aFirst - kR - 1,
+        isCommon
+      );
+  }
+  return iMaxR;
+};
+
+// A complete function to extend forward paths from (d - 1) to d changes.
+// Return true if a path overlaps reverse path of (d - 1) changes in its diagonal.
+const extendOverlappablePathsF = (
+  d,
+  aStart,
+  aEnd,
+  bStart,
+  bEnd,
+  isCommon,
+  aIndexesF,
+  iMaxF,
+  aIndexesR,
+  iMaxR,
+  division // update prop values if return true
+) => {
+  const bF = bStart - aStart; // bIndex = bF + aIndex - kF
+  const aLength = aEnd - aStart;
+  const bLength = bEnd - bStart;
+  const baDeltaLength = bLength - aLength; // kF = kR - baDeltaLength
+
+  // Range of diagonals in which forward and reverse paths might overlap.
+  const kMinOverlapF = -baDeltaLength - (d - 1); // -(d - 1) <= kR
+  const kMaxOverlapF = -baDeltaLength + (d - 1); // kR <= (d - 1)
+
+  let aIndexPrev1 = NOT_YET_SET; // prev value of [iF - 1] in next iteration
+
+  // Optimization: skip diagonals in which paths cannot ever overlap.
+  const nF = d < iMaxF ? d : iMaxF;
+
+  // The diagonals kF = 2 * iF - d are odd when d is odd and even when d is even.
+  for (let iF = 0, kF = -d; iF <= nF; iF += 1, kF += 2) {
+    // To get first point of path segment, move one change in forward direction
+    // from last point of previous path segment in an adjacent diagonal.
+    // In first iteration when iF === 0 and kF === -d always insert.
+    // In last possible iteration when iF === d and kF === d always delete.
+    const insert = iF === 0 || (iF !== d && aIndexPrev1 < aIndexesF[iF]);
+    const aLastPrev = insert ? aIndexesF[iF] : aIndexPrev1;
+    const aFirst = insert
+      ? aLastPrev // vertical to insert from b
+      : aLastPrev + 1; // horizontal to delete from a
+
+    // To get last point of path segment, move along diagonal of common items.
+    const bFirst = bF + aFirst - kF;
+    const nCommonF = countCommonItemsF(
+      aFirst + 1,
+      aEnd,
+      bFirst + 1,
+      bEnd,
+      isCommon
+    );
+    const aLast = aFirst + nCommonF;
+    aIndexPrev1 = aIndexesF[iF];
+    aIndexesF[iF] = aLast;
+    if (kMinOverlapF <= kF && kF <= kMaxOverlapF) {
+      // Solve for iR of reverse path with (d - 1) changes in diagonal kF:
+      // kR = kF + baDeltaLength
+      // kR = (d - 1) - 2 * iR
+      const iR = (d - 1 - (kF + baDeltaLength)) / 2;
+
+      // If this forward path overlaps the reverse path in this diagonal,
+      // then this is the middle change of the index intervals.
+      if (iR <= iMaxR && aIndexesR[iR] - 1 <= aLast) {
+        // Unlike the Myers algorithm which finds only the middle “snake”
+        // this package can find two common subsequences per division.
+        // Last point of previous path segment is on an adjacent diagonal.
+        const bLastPrev = bF + aLastPrev - (insert ? kF + 1 : kF - 1);
+
+        // Because of invariant that intervals preceding the middle change
+        // cannot have common items at the end,
+        // move in reverse direction along a diagonal of common items.
+        const nCommonR = countCommonItemsR(
+          aStart,
+          aLastPrev,
+          bStart,
+          bLastPrev,
+          isCommon
+        );
+        const aIndexPrevFirst = aLastPrev - nCommonR;
+        const bIndexPrevFirst = bLastPrev - nCommonR;
+        const aEndPreceding = aIndexPrevFirst + 1;
+        const bEndPreceding = bIndexPrevFirst + 1;
+        division.nChangePreceding = d - 1;
+        if (d - 1 === aEndPreceding + bEndPreceding - aStart - bStart) {
+          // Optimization: number of preceding changes in forward direction
+          // is equal to number of items in preceding interval,
+          // therefore it cannot contain any common items.
+          division.aEndPreceding = aStart;
+          division.bEndPreceding = bStart;
+        } else {
+          division.aEndPreceding = aEndPreceding;
+          division.bEndPreceding = bEndPreceding;
+        }
+        division.nCommonPreceding = nCommonR;
+        if (nCommonR !== 0) {
+          division.aCommonPreceding = aEndPreceding;
+          division.bCommonPreceding = bEndPreceding;
+        }
+        division.nCommonFollowing = nCommonF;
+        if (nCommonF !== 0) {
+          division.aCommonFollowing = aFirst + 1;
+          division.bCommonFollowing = bFirst + 1;
+        }
+        const aStartFollowing = aLast + 1;
+        const bStartFollowing = bFirst + nCommonF + 1;
+        division.nChangeFollowing = d - 1;
+        if (d - 1 === aEnd + bEnd - aStartFollowing - bStartFollowing) {
+          // Optimization: number of changes in reverse direction
+          // is equal to number of items in following interval,
+          // therefore it cannot contain any common items.
+          division.aStartFollowing = aEnd;
+          division.bStartFollowing = bEnd;
+        } else {
+          division.aStartFollowing = aStartFollowing;
+          division.bStartFollowing = bStartFollowing;
+        }
+        return true;
+      }
+    }
+  }
+  return false;
+};
+
+// A complete function to extend reverse paths from (d - 1) to d changes.
+// Return true if a path overlaps forward path of d changes in its diagonal.
+const extendOverlappablePathsR = (
+  d,
+  aStart,
+  aEnd,
+  bStart,
+  bEnd,
+  isCommon,
+  aIndexesF,
+  iMaxF,
+  aIndexesR,
+  iMaxR,
+  division // update prop values if return true
+) => {
+  const bR = bEnd - aEnd; // bIndex = bR + aIndex - kR
+  const aLength = aEnd - aStart;
+  const bLength = bEnd - bStart;
+  const baDeltaLength = bLength - aLength; // kR = kF + baDeltaLength
+
+  // Range of diagonals in which forward and reverse paths might overlap.
+  const kMinOverlapR = baDeltaLength - d; // -d <= kF
+  const kMaxOverlapR = baDeltaLength + d; // kF <= d
+
+  let aIndexPrev1 = NOT_YET_SET; // prev value of [iR - 1] in next iteration
+
+  // Optimization: skip diagonals in which paths cannot ever overlap.
+  const nR = d < iMaxR ? d : iMaxR;
+
+  // The diagonals kR = d - 2 * iR are odd when d is odd and even when d is even.
+  for (let iR = 0, kR = d; iR <= nR; iR += 1, kR -= 2) {
+    // To get first point of path segment, move one change in reverse direction
+    // from last point of previous path segment in an adjacent diagonal.
+    // In first iteration when iR === 0 and kR === d always insert.
+    // In last possible iteration when iR === d and kR === -d always delete.
+    const insert = iR === 0 || (iR !== d && aIndexesR[iR] < aIndexPrev1);
+    const aLastPrev = insert ? aIndexesR[iR] : aIndexPrev1;
+    const aFirst = insert
+      ? aLastPrev // vertical to insert from b
+      : aLastPrev - 1; // horizontal to delete from a
+
+    // To get last point of path segment, move along diagonal of common items.
+    const bFirst = bR + aFirst - kR;
+    const nCommonR = countCommonItemsR(
+      aStart,
+      aFirst - 1,
+      bStart,
+      bFirst - 1,
+      isCommon
+    );
+    const aLast = aFirst - nCommonR;
+    aIndexPrev1 = aIndexesR[iR];
+    aIndexesR[iR] = aLast;
+    if (kMinOverlapR <= kR && kR <= kMaxOverlapR) {
+      // Solve for iF of forward path with d changes in diagonal kR:
+      // kF = kR - baDeltaLength
+      // kF = 2 * iF - d
+      const iF = (d + (kR - baDeltaLength)) / 2;
+
+      // If this reverse path overlaps the forward path in this diagonal,
+      // then this is a middle change of the index intervals.
+      if (iF <= iMaxF && aLast - 1 <= aIndexesF[iF]) {
+        const bLast = bFirst - nCommonR;
+        division.nChangePreceding = d;
+        if (d === aLast + bLast - aStart - bStart) {
+          // Optimization: number of changes in reverse direction
+          // is equal to number of items in preceding interval,
+          // therefore it cannot contain any common items.
+          division.aEndPreceding = aStart;
+          division.bEndPreceding = bStart;
+        } else {
+          division.aEndPreceding = aLast;
+          division.bEndPreceding = bLast;
+        }
+        division.nCommonPreceding = nCommonR;
+        if (nCommonR !== 0) {
+          // The last point of reverse path segment is start of common subsequence.
+          division.aCommonPreceding = aLast;
+          division.bCommonPreceding = bLast;
+        }
+        division.nChangeFollowing = d - 1;
+        if (d === 1) {
+          // There is no previous path segment.
+          division.nCommonFollowing = 0;
+          division.aStartFollowing = aEnd;
+          division.bStartFollowing = bEnd;
+        } else {
+          // Unlike the Myers algorithm which finds only the middle “snake”
+          // this package can find two common subsequences per division.
+          // Last point of previous path segment is on an adjacent diagonal.
+          const bLastPrev = bR + aLastPrev - (insert ? kR - 1 : kR + 1);
+
+          // Because of invariant that intervals following the middle change
+          // cannot have common items at the start,
+          // move in forward direction along a diagonal of common items.
+          const nCommonF = countCommonItemsF(
+            aLastPrev,
+            aEnd,
+            bLastPrev,
+            bEnd,
+            isCommon
+          );
+          division.nCommonFollowing = nCommonF;
+          if (nCommonF !== 0) {
+            // The last point of reverse path segment is start of common subsequence.
+            division.aCommonFollowing = aLastPrev;
+            division.bCommonFollowing = bLastPrev;
+          }
+          const aStartFollowing = aLastPrev + nCommonF; // aFirstPrev
+          const bStartFollowing = bLastPrev + nCommonF; // bFirstPrev
+
+          if (d - 1 === aEnd + bEnd - aStartFollowing - bStartFollowing) {
+            // Optimization: number of changes in forward direction
+            // is equal to number of items in following interval,
+            // therefore it cannot contain any common items.
+            division.aStartFollowing = aEnd;
+            division.bStartFollowing = bEnd;
+          } else {
+            division.aStartFollowing = aStartFollowing;
+            division.bStartFollowing = bStartFollowing;
+          }
+        }
+        return true;
+      }
+    }
+  }
+  return false;
+};
+
+// Given index intervals and input function to compare items at indexes,
+// divide at the middle change.
+//
+// DO NOT CALL if start === end, because interval cannot contain common items
+// and because this function will throw the “no overlap” error.
+const divide = (
+  nChange,
+  aStart,
+  aEnd,
+  bStart,
+  bEnd,
+  isCommon,
+  aIndexesF,
+  aIndexesR,
+  division // output
+) => {
+  const bF = bStart - aStart; // bIndex = bF + aIndex - kF
+  const bR = bEnd - aEnd; // bIndex = bR + aIndex - kR
+  const aLength = aEnd - aStart;
+  const bLength = bEnd - bStart;
+
+  // Because graph has square or portrait orientation,
+  // length difference is minimum number of items to insert from b.
+  // Corresponding forward and reverse diagonals in graph
+  // depend on length difference of the sequences:
+  // kF = kR - baDeltaLength
+  // kR = kF + baDeltaLength
+  const baDeltaLength = bLength - aLength;
+
+  // Optimization: max diagonal in graph intersects corner of shorter side.
+  let iMaxF = aLength;
+  let iMaxR = aLength;
+
+  // Initialize no changes yet in forward or reverse direction:
+  aIndexesF[0] = aStart - 1; // at open start of interval, outside closed start
+  aIndexesR[0] = aEnd; // at open end of interval
+
+  if (baDeltaLength % 2 === 0) {
+    // The number of changes in paths is 2 * d if length difference is even.
+    const dMin = (nChange || baDeltaLength) / 2;
+    const dMax = (aLength + bLength) / 2;
+    for (let d = 1; d <= dMax; d += 1) {
+      iMaxF = extendPathsF(d, aEnd, bEnd, bF, isCommon, aIndexesF, iMaxF);
+      if (d < dMin) {
+        iMaxR = extendPathsR(d, aStart, bStart, bR, isCommon, aIndexesR, iMaxR);
+      } else if (
+        // If a reverse path overlaps a forward path in the same diagonal,
+        // return a division of the index intervals at the middle change.
+        extendOverlappablePathsR(
+          d,
+          aStart,
+          aEnd,
+          bStart,
+          bEnd,
+          isCommon,
+          aIndexesF,
+          iMaxF,
+          aIndexesR,
+          iMaxR,
+          division
+        )
+      ) {
+        return;
+      }
+    }
+  } else {
+    // The number of changes in paths is 2 * d - 1 if length difference is odd.
+    const dMin = ((nChange || baDeltaLength) + 1) / 2;
+    const dMax = (aLength + bLength + 1) / 2;
+
+    // Unroll first half iteration so loop extends the relevant pairs of paths.
+    // Because of invariant that intervals have no common items at start or end,
+    // and limitation not to call divide with empty intervals,
+    // therefore it cannot be called if a forward path with one change
+    // would overlap a reverse path with no changes, even if dMin === 1.
+    let d = 1;
+    iMaxF = extendPathsF(d, aEnd, bEnd, bF, isCommon, aIndexesF, iMaxF);
+    for (d += 1; d <= dMax; d += 1) {
+      iMaxR = extendPathsR(
+        d - 1,
+        aStart,
+        bStart,
+        bR,
+        isCommon,
+        aIndexesR,
+        iMaxR
+      );
+      if (d < dMin) {
+        iMaxF = extendPathsF(d, aEnd, bEnd, bF, isCommon, aIndexesF, iMaxF);
+      } else if (
+        // If a forward path overlaps a reverse path in the same diagonal,
+        // return a division of the index intervals at the middle change.
+        extendOverlappablePathsF(
+          d,
+          aStart,
+          aEnd,
+          bStart,
+          bEnd,
+          isCommon,
+          aIndexesF,
+          iMaxF,
+          aIndexesR,
+          iMaxR,
+          division
+        )
+      ) {
+        return;
+      }
+    }
+  }
+
+  /* istanbul ignore next */
+  throw new Error(
+    `${pkg}: no overlap aStart=${aStart} aEnd=${aEnd} bStart=${bStart} bEnd=${bEnd}`
+  );
+};
+
+// Given index intervals and input function to compare items at indexes,
+// return by output function the number of adjacent items and starting indexes
+// of each common subsequence. Divide and conquer with only linear space.
+//
+// The index intervals are half open [start, end) like array slice method.
+// DO NOT CALL if start === end, because interval cannot contain common items
+// and because divide function will throw the “no overlap” error.
+const findSubsequences = (
+  nChange,
+  aStart,
+  aEnd,
+  bStart,
+  bEnd,
+  transposed,
+  callbacks,
+  aIndexesF,
+  aIndexesR,
+  division // temporary memory, not input nor output
+) => {
+  if (bEnd - bStart < aEnd - aStart) {
+    // Transpose graph so it has portrait instead of landscape orientation.
+    // Always compare shorter to longer sequence for consistency and optimization.
+    transposed = !transposed;
+    if (transposed && callbacks.length === 1) {
+      // Lazily wrap callback functions to swap args if graph is transposed.
+      const {foundSubsequence, isCommon} = callbacks[0];
+      callbacks[1] = {
+        foundSubsequence: (nCommon, bCommon, aCommon) => {
+          foundSubsequence(nCommon, aCommon, bCommon);
+        },
+        isCommon: (bIndex, aIndex) => isCommon(aIndex, bIndex)
+      };
+    }
+    const tStart = aStart;
+    const tEnd = aEnd;
+    aStart = bStart;
+    aEnd = bEnd;
+    bStart = tStart;
+    bEnd = tEnd;
+  }
+  const {foundSubsequence, isCommon} = callbacks[transposed ? 1 : 0];
+
+  // Divide the index intervals at the middle change.
+  divide(
+    nChange,
+    aStart,
+    aEnd,
+    bStart,
+    bEnd,
+    isCommon,
+    aIndexesF,
+    aIndexesR,
+    division
+  );
+  const {
+    nChangePreceding,
+    aEndPreceding,
+    bEndPreceding,
+    nCommonPreceding,
+    aCommonPreceding,
+    bCommonPreceding,
+    nCommonFollowing,
+    aCommonFollowing,
+    bCommonFollowing,
+    nChangeFollowing,
+    aStartFollowing,
+    bStartFollowing
+  } = division;
+
+  // Unless either index interval is empty, they might contain common items.
+  if (aStart < aEndPreceding && bStart < bEndPreceding) {
+    // Recursely find and return common subsequences preceding the division.
+    findSubsequences(
+      nChangePreceding,
+      aStart,
+      aEndPreceding,
+      bStart,
+      bEndPreceding,
+      transposed,
+      callbacks,
+      aIndexesF,
+      aIndexesR,
+      division
+    );
+  }
+
+  // Return common subsequences that are adjacent to the middle change.
+  if (nCommonPreceding !== 0) {
+    foundSubsequence(nCommonPreceding, aCommonPreceding, bCommonPreceding);
+  }
+  if (nCommonFollowing !== 0) {
+    foundSubsequence(nCommonFollowing, aCommonFollowing, bCommonFollowing);
+  }
+
+  // Unless either index interval is empty, they might contain common items.
+  if (aStartFollowing < aEnd && bStartFollowing < bEnd) {
+    // Recursely find and return common subsequences following the division.
+    findSubsequences(
+      nChangeFollowing,
+      aStartFollowing,
+      aEnd,
+      bStartFollowing,
+      bEnd,
+      transposed,
+      callbacks,
+      aIndexesF,
+      aIndexesR,
+      division
+    );
+  }
+};
+const validateLength = (name, arg) => {
+  if (typeof arg !== 'number') {
+    throw new TypeError(`${pkg}: ${name} typeof ${typeof arg} is not a number`);
+  }
+  if (!Number.isSafeInteger(arg)) {
+    throw new RangeError(`${pkg}: ${name} value ${arg} is not a safe integer`);
+  }
+  if (arg < 0) {
+    throw new RangeError(`${pkg}: ${name} value ${arg} is a negative integer`);
+  }
+};
+const validateCallback = (name, arg) => {
+  const type = typeof arg;
+  if (type !== 'function') {
+    throw new TypeError(`${pkg}: ${name} typeof ${type} is not a function`);
+  }
+};
+
+// Compare items in two sequences to find a longest common subsequence.
+// Given lengths of sequences and input function to compare items at indexes,
+// return by output function the number of adjacent items and starting indexes
+// of each common subsequence.
+function diffSequence(aLength, bLength, isCommon, foundSubsequence) {
+  validateLength('aLength', aLength);
+  validateLength('bLength', bLength);
+  validateCallback('isCommon', isCommon);
+  validateCallback('foundSubsequence', foundSubsequence);
+
+  // Count common items from the start in the forward direction.
+  const nCommonF = countCommonItemsF(0, aLength, 0, bLength, isCommon);
+  if (nCommonF !== 0) {
+    foundSubsequence(nCommonF, 0, 0);
+  }
+
+  // Unless both sequences consist of common items only,
+  // find common items in the half-trimmed index intervals.
+  if (aLength !== nCommonF || bLength !== nCommonF) {
+    // Invariant: intervals do not have common items at the start.
+    // The start of an index interval is closed like array slice method.
+    const aStart = nCommonF;
+    const bStart = nCommonF;
+
+    // Count common items from the end in the reverse direction.
+    const nCommonR = countCommonItemsR(
+      aStart,
+      aLength - 1,
+      bStart,
+      bLength - 1,
+      isCommon
+    );
+
+    // Invariant: intervals do not have common items at the end.
+    // The end of an index interval is open like array slice method.
+    const aEnd = aLength - nCommonR;
+    const bEnd = bLength - nCommonR;
+
+    // Unless one sequence consists of common items only,
+    // therefore the other trimmed index interval consists of changes only,
+    // find common items in the trimmed index intervals.
+    const nCommonFR = nCommonF + nCommonR;
+    if (aLength !== nCommonFR && bLength !== nCommonFR) {
+      const nChange = 0; // number of change items is not yet known
+      const transposed = false; // call the original unwrapped functions
+      const callbacks = [
+        {
+          foundSubsequence,
+          isCommon
+        }
+      ];
+
+      // Indexes in sequence a of last points in furthest reaching paths
+      // from outside the start at top left in the forward direction:
+      const aIndexesF = [NOT_YET_SET];
+      // from the end at bottom right in the reverse direction:
+      const aIndexesR = [NOT_YET_SET];
+
+      // Initialize one object as output of all calls to divide function.
+      const division = {
+        aCommonFollowing: NOT_YET_SET,
+        aCommonPreceding: NOT_YET_SET,
+        aEndPreceding: NOT_YET_SET,
+        aStartFollowing: NOT_YET_SET,
+        bCommonFollowing: NOT_YET_SET,
+        bCommonPreceding: NOT_YET_SET,
+        bEndPreceding: NOT_YET_SET,
+        bStartFollowing: NOT_YET_SET,
+        nChangeFollowing: NOT_YET_SET,
+        nChangePreceding: NOT_YET_SET,
+        nCommonFollowing: NOT_YET_SET,
+        nCommonPreceding: NOT_YET_SET
+      };
+
+      // Find and return common subsequences in the trimmed index intervals.
+      findSubsequences(
+        nChange,
+        aStart,
+        aEnd,
+        bStart,
+        bEnd,
+        transposed,
+        callbacks,
+        aIndexesF,
+        aIndexesR,
+        division
+      );
+    }
+    if (nCommonR !== 0) {
+      foundSubsequence(nCommonR, aEnd, bEnd);
+    }
+  }
+}

backend/apis/nodejs/node_modules/diff-sequences/package.json

@@ -0,0 +1,39 @@
+{
+  "name": "diff-sequences",
+  "version": "29.6.3",
+  "repository": {
+    "type": "git",
+    "url": "https://github.com/jestjs/jest.git",
+    "directory": "packages/diff-sequences"
+  },
+  "license": "MIT",
+  "description": "Compare items in two sequences to find a longest common subsequence",
+  "keywords": [
+    "fast",
+    "linear",
+    "space",
+    "callback",
+    "diff"
+  ],
+  "engines": {
+    "node": "^14.15.0 || ^16.10.0 || >=18.0.0"
+  },
+  "main": "./build/index.js",
+  "types": "./build/index.d.ts",
+  "exports": {
+    ".": {
+      "types": "./build/index.d.ts",
+      "default": "./build/index.js"
+    },
+    "./package.json": "./package.json"
+  },
+  "devDependencies": {
+    "@fast-check/jest": "^1.3.0",
+    "benchmark": "^2.1.4",
+    "diff": "^5.0.0"
+  },
+  "publishConfig": {
+    "access": "public"
+  },
+  "gitHead": "fb7d95c8af6e0d65a8b65348433d8a0ea0725b5b"
+}