common/scope_exit: Replace std::move with std::forward in ScopeExit()
The template type here is actually a forwarding reference, not an rvalue reference in this case, so it's more appropriate to use std::forward to preserve the value category of the type being moved.
This commit is contained in:
		| @@ -20,7 +20,7 @@ struct ScopeExitHelper { | |||||||
|  |  | ||||||
| template <typename Func> | template <typename Func> | ||||||
| ScopeExitHelper<Func> ScopeExit(Func&& func) { | ScopeExitHelper<Func> ScopeExit(Func&& func) { | ||||||
|     return ScopeExitHelper<Func>(std::move(func)); |     return ScopeExitHelper<Func>(std::forward<Func>(func)); | ||||||
| } | } | ||||||
| } // namespace detail | } // namespace detail | ||||||
|  |  | ||||||
|   | |||||||
		Reference in New Issue
	
	Block a user