57 lines
1.7 KiB
Go
57 lines
1.7 KiB
Go
////////////////////////////////////////////////////////////////////////////
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// Porgram: xmlfmt.go
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// Purpose: Go XML Beautify from XML string using pure string manipulation
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// Authors: Antonio Sun (c) 2016-2019, All rights reserved
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////////////////////////////////////////////////////////////////////////////
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package xmlfmt
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import (
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"regexp"
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"strings"
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)
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var (
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reg = regexp.MustCompile(`<([/!]?)([^>]+?)(/?)>`)
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// NL is the newline string used in XML output, define for DOS-convenient.
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NL = "\r\n"
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)
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// FormatXML will (purly) reformat the XML string in a readable way, without any rewriting/altering the structure
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func FormatXML(xmls, prefix, indent string) string {
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src := regexp.MustCompile(`(?s)>\s+<`).ReplaceAllString(xmls, "><")
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rf := replaceTag(prefix, indent)
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return (prefix + reg.ReplaceAllStringFunc(src, rf))
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}
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// replaceTag returns a closure function to do 's/(?<=>)\s+(?=<)//g; s(<(/?)([^>]+?)(/?)>)($indent+=$3?0:$1?-1:1;"<$1$2$3>"."\n".(" "x$indent))ge' as in Perl
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// and deal with comments as well
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func replaceTag(prefix, indent string) func(string) string {
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indentLevel := 0
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return func(m string) string {
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// head elem
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if strings.HasPrefix(m, "<?xml") {
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return NL + prefix + strings.Repeat(indent, indentLevel) + m
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}
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// empty elem
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if strings.HasSuffix(m, "/>") {
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return NL + prefix + strings.Repeat(indent, indentLevel) + m
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}
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// comment elem
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if strings.HasPrefix(m, "<!") {
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return NL + prefix + strings.Repeat(indent, indentLevel) + m
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}
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// end elem
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if strings.HasPrefix(m, "</") {
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indentLevel--
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return NL + prefix + strings.Repeat(indent, indentLevel) + m
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}
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defer func() {
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indentLevel++
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}()
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return NL + prefix + strings.Repeat(indent, indentLevel) + m
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}
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}
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