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separate each file compression into a subtask

This commit is contained in:
codl 2017-08-11 20:29:48 +02:00
parent 0cfdb90efd
commit 5ee7041e20
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1 changed files with 16 additions and 8 deletions
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20
dodo.py
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@ -52,8 +52,7 @@ def task_compress_static():
import brotli import brotli
import gzip import gzip
deps = ('static/styles.css', 'static/icon.png', 'static/logotype.png') + tuple((f'static/logotype-{width}.png' for width in (200, 400, 600, 800))) files = ('static/styles.css', 'static/icon.png', 'static/logotype.png') + tuple((f'static/logotype-{width}.png' for width in (200, 400, 600, 800)))
targets = tuple((f'{file}.br' for file in deps)) + tuple((f'{file}.gz' for file in deps))
def compress_brotli(dependencies): def compress_brotli(dependencies):
for filename in dependencies: for filename in dependencies:
@ -66,10 +65,19 @@ def task_compress_static():
with gzip.open(filename + '.gz', 'wb') as out: with gzip.open(filename + '.gz', 'wb') as out:
out.write(in_.read()) out.write(in_.read())
return dict( for filename in files:
file_dep=deps, yield dict(
targets=targets, file_dep=(filename,),
actions=[compress_brotli, compress_gzip], targets=(filename+'.br',),
name=filename+'.br',
actions=[compress_brotli],
clean=True,
)
yield dict(
file_dep=(filename,),
targets=(filename+'.gz',),
name=filename+'.gz',
actions=[compress_gzip],
clean=True, clean=True,
) )