newlib/libgloss/testsuite/libgloss.all/misc.c
2000-03-17 22:48:54 +00:00

168 lines
3.7 KiB
C

/*
* this file contains misc bug reports from WinBond.
*/
#include <stdio.h>
#include <math.h>
#if unix
#define pass(x) printf("PASS: %s\n", x);
#define fail(x) printf("FAIL: %s\n", x);
#endif
/*
The compare operation is error. Because the constant value 1.0 is
not correct. It seems compare with 0 in this statement.
HP-UX native:
dist is 0.301
PASS: float compare
*cp = be9a1cac, *cp1 = be9a1cac
PASS: float multiple 1
PASS: float multiple 2
32760 / (-2) = -16380
PASS: float divide 1
32760 / (-1) = -32760
PASS: float divide 1
These test only pass if the output matches:
Correct output is
1.0 = 1.000000E+00, 0.3010 = 3.000000E-01, -1.0 = -1.000000E+0
1.0 = 1.000000E+00, 0.3010 = 3.010000E-01, -1.0 = -1.000000E+00
These test only pass if the outut matches:
Correct output is
ans = 1.000000E+00, ans1 = 3.010000E-01, ans2 = -1.000000E+00
ans = 1.000000E+00, ans1 = 3.010000E-01, ans2 = -1.000000E+00
Test run on Oki:
dist is 0
PASS: float compare
*cp = be9a1cac, *cp1 = be9a1cac
PASS: float multiple 1
PASS: float multiple 2
32760 / (-2) = -2147467268
PASS: float divide 1
32760 / (-1) = 32760
PASS: float divide 1
These test only pass if the output matches:
Correct output is
1.0 = 1.000000E+00, 0.3010 = 3.000000E-01, -1.0 = -1.000000E+0
1.0 = 1.586860E-318, 0.3010 = -1.009091E-303, -1.0 = 5.290504E-315
These test only pass if the outut matches:
Correct output is
ans = 1.000000E+00, ans1 = 3.010000E-01, ans2 = -1.000000E+00
ans = 4.940656E-324, ans1 = -5.299809E-315, ans2 = 5.290504E-315
*/
main()
{
float dist = 0.3010;
printf ("dist is %G\n", dist);
if ( dist < 1.0 ) {
pass ("float compare");
} else {
fail ("float compare");
}
test_1();
test_2();
test_3();
test_4();
fflush (stdout);
}
/*
* *cp = be9a1cac, *cp1 = 00000000
*/
test_1()
{
float i, ans, ans1;
unsigned int *cp=&ans, *cp1=&ans1;
i = 0.3010;
ans = (-1.0) * 0.3010 * 1.0; /* OK */
ans1 = (-1.0) * i * 1.0; /* Disaster */
printf ("*cp = %08x, *cp1 = %08x\n", *cp, *cp1);
if (*cp != 0xbe9a1cac) {
fail ("float multiple 1");
} else {
pass ("float multiple 1");
}
if (*cp1 != 0xbe9a1cac) {
fail ("float multiple 2");
} else {
pass ("float multiple 2");
}
}
/*
Positive integer divide Negative integer may get interesting result.
For examples:
EX1: 32760 / (-2) = -2147467268
*/
test_2()
{
int value, i, j;
i = 32760;
j = -2;
value = i / (j);
printf ("%d / (%d) = %d\n", i, j, value);
if (value != -16380) {
fail ("float divide 1");
} else {
pass ("float divide 1");
}
}
/*
EX2: 32760 / (-1) = 32760
*/
test_3()
{
int value, i, j;
i = 32760;
j = -1;
value = i / (j);
printf ("%d / (%d) = %d\n", i, j, value);
if (value != -32760) {
fail ("float divide 1");
} else {
pass ("float divide 1");
}
}
/*
The data output format %e, %E, %g, %G in printf() can not work.
Please test the following example:
1.0 = 1.000000E+00, 0.3010 = 3.009999E-01, -1.0 = -1.000000E+00
ans = 4.940656E-324, ans1 = -5.299809E-315, ans2 = 5.290504E-315
*/
test_4()
{
float ans, ans1, ans2;
ans = 1.0;
ans1 = 0.3010;
ans2 = -1.0;
printf ("These test only pass if the output matches:\nCorrect output is\n1.0 = 1.000000E+00, 0.3010 = 3.000000E-01, -1.0 = -1.000000E+0\n");
printf ("1.0 = %E, 0.3010 = %E, -1.0 = %E\n", 1.0, 0.3010, -1.0);
printf ("These test only pass if the outut matches:\nCorrect output is\nans = 1.000000E+00, ans1 = 3.010000E-01, ans2 = -1.000000E+00\n");
printf ("ans = %E, ans1 = %E, ans2 = %E\n", ans, ans1, ans2);
}