69 lines
1.3 KiB
C
69 lines
1.3 KiB
C
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#include <u.h>
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#include <libc.h>
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#include <draw.h>
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#include <memdraw.h>
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Memsubfont*
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getmemdefont(void)
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{
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char *hdr, *p;
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int n;
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Fontchar *fc;
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Memsubfont *f;
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int ld;
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Rectangle r;
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Memdata *md;
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Memimage *i;
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/*
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* make sure data is word-aligned. this is true with Plan 9 compilers
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* but not in general. the byte order is right because the data is
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* declared as char*, not ulong*.
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*/
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p = (char*)defontdata;
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n = (ulong)p & 3;
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if(n != 0){
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memmove(p+(4-n), p, sizeofdefont-n);
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p += 4-n;
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}
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ld = atoi(p+0*12);
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r.min.x = atoi(p+1*12);
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r.min.y = atoi(p+2*12);
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r.max.x = atoi(p+3*12);
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r.max.y = atoi(p+4*12);
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md = mallocz(sizeof(Memdata), 1);
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if(md == nil)
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return nil;
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p += 5*12;
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md->base = nil; /* so freememimage doesn't free p */
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md->bdata = (uchar*)p; /* ick */
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md->ref = 1;
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md->allocd = 1; /* so freememimage does free md */
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i = allocmemimaged(r, drawld2chan[ld], md, nil);
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if(i == nil){
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free(md);
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return nil;
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}
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hdr = p+Dy(r)*i->width*sizeof(ulong);
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n = atoi(hdr);
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p = hdr+3*12;
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fc = malloc(sizeof(Fontchar)*(n+1));
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if(fc == 0){
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freememimage(i);
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return 0;
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}
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_unpackinfo(fc, (uchar*)p, n);
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f = allocmemsubfont("*default*", n, atoi(hdr+12), atoi(hdr+24), fc, i);
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if(f == 0){
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freememimage(i);
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free(fc);
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return 0;
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}
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return f;
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}
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